4(x-3)-(x-2)=2(x-1)

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Solution for 4(x-3)-(x-2)=2(x-1) equation: 



4(x-3)-(x-2)=2(x-1)

We move all terms to the left:

4(x-3)-(x-2)-(2(x-1))=0

We multiply parentheses

4x-(x-2)-(2(x-1))-12=0

We get rid of parentheses

4x-x-(2(x-1))+2-12=0



We calculate terms in parentheses: -(2(x-1)), so:

2(x-1)

We multiply parentheses

2x-2

Back to the equation:

-(2x-2)



We add all the numbers together, and all the variables

3x-(2x-2)-10=0

We get rid of parentheses

3x-2x+2-10=0

We add all the numbers together, and all the variables

x-8=0

We move all terms containing x to the left, all other terms to the right

x=8

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