3(y+5)=-2(y+10)

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Solution for 3(y+5)=-2(y+10) equation: 



3(y+5)=-2(y+10)

We move all terms to the left:

3(y+5)-(-2(y+10))=0

We multiply parentheses

3y-(-2(y+10))+15=0



We calculate terms in parentheses: -(-2(y+10)), so:

-2(y+10)

We multiply parentheses

-2y-20

Back to the equation:

-(-2y-20)



We get rid of parentheses

3y+2y+20+15=0

We add all the numbers together, and all the variables

5y+35=0

We move all terms containing y to the left, all other terms to the right

5y=-35

y=-35/5

y=-7

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