6x-(3/2)x=(3/2)x+28

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Solution for 6x-(3/2)x=(3/2)x+28 equation: 



6x-(3/2)x=(3/2)x+28

We move all terms to the left:

6x-(3/2)x-((3/2)x+28)=0



Domain of the equation: 2)x!=0

x!=0/1

x!=0

x∈R





Domain of the equation: 2)x+28)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

6x-(+3/2)x-((+3/2)x+28)=0

We multiply parentheses

-3x^2+6x-((+3/2)x+28)=0

We multiply all the terms by the denominator


-3x^2*2)x+28)+6x*2)x+28)-((+3=0

Wy multiply elements

-12x^4=0

We do not support expression: x^4

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