1/2(16x+22)=3/4(16x-12)

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Solution for 1/2(16x+22)=3/4(16x-12) equation: 



1/2(16x+22)=3/4(16x-12)

We move all terms to the left:

1/2(16x+22)-(3/4(16x-12))=0



Domain of the equation: 2(16x+22)!=0

x∈R





Domain of the equation: 4(16x-12))!=0

x∈R



We calculate fractions


(4x1/(2(16x+22)*4(16x-12)))+(-6x1/(2(16x+22)*4(16x-12)))=0



We calculate terms in parentheses: +(4x1/(2(16x+22)*4(16x-12))), so:

4x1/(2(16x+22)*4(16x-12))

We multiply all the terms by the denominator


4x1

We add all the numbers together, and all the variables

4x

Back to the equation:

+(4x)





We calculate terms in parentheses: +(-6x1/(2(16x+22)*4(16x-12))), so:

-6x1/(2(16x+22)*4(16x-12))

We multiply all the terms by the denominator


-6x1

We add all the numbers together, and all the variables

-6x

Back to the equation:

+(-6x)



We get rid of parentheses

4x-6x=0

We add all the numbers together, and all the variables

-2x=0

x=0/-2

x=0

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