2+2(4x-5)=8-4(2x+1)

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Solution for 2+2(4x-5)=8-4(2x+1) equation: 



2+2(4x-5)=8-4(2x+1)

We move all terms to the left:

2+2(4x-5)-(8-4(2x+1))=0

We multiply parentheses

8x-(8-4(2x+1))-10+2=0



We calculate terms in parentheses: -(8-4(2x+1)), so:

8-4(2x+1)

determiningTheFunctionDomain
-4(2x+1)+8

We multiply parentheses

-8x-4+8

We add all the numbers together, and all the variables

-8x+4

Back to the equation:

-(-8x+4)



We add all the numbers together, and all the variables

8x-(-8x+4)-8=0

We get rid of parentheses

8x+8x-4-8=0

We add all the numbers together, and all the variables

16x-12=0

We move all terms containing x to the left, all other terms to the right

16x=12

x=12/16

x=3/4

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