6x+3-3(-2x-3)=2(x-1)

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Solution for 6x+3-3(-2x-3)=2(x-1) equation: 



6x+3-3(-2x-3)=2(x-1)

We move all terms to the left:

6x+3-3(-2x-3)-(2(x-1))=0

We multiply parentheses

6x+6x-(2(x-1))+9+3=0



We calculate terms in parentheses: -(2(x-1)), so:

2(x-1)

We multiply parentheses

2x-2

Back to the equation:

-(2x-2)



We add all the numbers together, and all the variables

12x-(2x-2)+12=0

We get rid of parentheses

12x-2x+2+12=0

We add all the numbers together, and all the variables

10x+14=0

We move all terms containing x to the left, all other terms to the right

10x=-14

x=-14/10

x=-1+2/5

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