11(z+3)-3(2-1)=4(2-4)+3(z-3)

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Solution for 11(z+3)-3(2-1)=4(2-4)+3(z-3) equation: 



11(z+3)-3(2-1)=4(2-4)+3(z-3)

We move all terms to the left:

11(z+3)-3(2-1)-(4(2-4)+3(z-3))=0

We add all the numbers together, and all the variables

11(z+3)-(4(-2)+3(z-3))-31=0

We multiply parentheses

11z-(4(-2)+3(z-3))+33-31=0



We calculate terms in parentheses: -(4(-2)+3(z-3)), so:

4(-2)+3(z-3)

determiningTheFunctionDomain
3(z-3)+4(-2)

We add all the numbers together, and all the variables

3(z-3)-8

We multiply parentheses

3z-9-8

We add all the numbers together, and all the variables

3z-17

Back to the equation:

-(3z-17)



We add all the numbers together, and all the variables

11z-(3z-17)+2=0

We get rid of parentheses

11z-3z+17+2=0

We add all the numbers together, and all the variables

8z+19=0

We move all terms containing z to the left, all other terms to the right

8z=-19

z=-19/8

z=-2+3/8

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