10(v+2)-2v=2(4v+3)-8

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Solution for 10(v+2)-2v=2(4v+3)-8 equation: 



10(v+2)-2v=2(4v+3)-8

We move all terms to the left:

10(v+2)-2v-(2(4v+3)-8)=0

We add all the numbers together, and all the variables

-2v+10(v+2)-(2(4v+3)-8)=0

We multiply parentheses

-2v+10v-(2(4v+3)-8)+20=0



We calculate terms in parentheses: -(2(4v+3)-8), so:

2(4v+3)-8

We multiply parentheses

8v+6-8

We add all the numbers together, and all the variables

8v-2

Back to the equation:

-(8v-2)



We add all the numbers together, and all the variables

8v-(8v-2)+20=0

We get rid of parentheses

8v-8v+2+20=0

We add all the numbers together, and all the variables

22!=0

There is no solution for this equation

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