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6w^2+13w+6=0
a = 6; b = 13; c = +6;
Δ = b2-4ac
Δ = 132-4·6·6
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-5}{2*6}=\frac{-18}{12} =-1+1/2 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+5}{2*6}=\frac{-8}{12} =-2/3 $
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