3(2x-7)=4(4x-2)

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Solution for 3(2x-7)=4(4x-2) equation: 



3(2x-7)=4(4x-2)

We move all terms to the left:

3(2x-7)-(4(4x-2))=0

We multiply parentheses

6x-(4(4x-2))-21=0



We calculate terms in parentheses: -(4(4x-2)), so:

4(4x-2)

We multiply parentheses

16x-8

Back to the equation:

-(16x-8)



We get rid of parentheses

6x-16x+8-21=0

We add all the numbers together, and all the variables

-10x-13=0

We move all terms containing x to the left, all other terms to the right

-10x=13

x=13/-10

x=-1+3/10

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