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5(2-(2x+4))=2(5-3x)
We move all terms to the left:
5(2-(2x+4))-(2(5-3x))=0
We add all the numbers together, and all the variables
5(2-(2x+4))-(2(-3x+5))=0
We calculate terms in parentheses: -(2(-3x+5)), so:We get rid of parentheses
2(-3x+5)
We multiply parentheses
-6x+10
Back to the equation:
-(-6x+10)
5(2-(2x+4))+6x-10=0
We add all the numbers together, and all the variables
6x+5(2-(2x+4))-10=0
We move all terms containing x to the left, all other terms to the right
6x+5(2-(2x+4))=10
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