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6v-2+2=2(3v-5)
We move all terms to the left:
6v-2+2-(2(3v-5))=0
We add all the numbers together, and all the variables
6v-(2(3v-5))=0
We calculate terms in parentheses: -(2(3v-5)), so:We get rid of parentheses
2(3v-5)
We multiply parentheses
6v-10
Back to the equation:
-(6v-10)
6v-6v+10=0
We add all the numbers together, and all the variables
10!=0
There is no solution for this equation
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