105=1/2((3x+15)(x+2))

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Solution for 105=1/2((3x+15)(x+2)) equation: 



105=1/2((3x+15)(x+2))

We move all terms to the left:

105-(1/2((3x+15)(x+2)))=0



Domain of the equation: 2((3x+15)(x+2)))!=0

x∈R



We multiply parentheses ..

-(1/2((+3x^2+6x+15x+30)))+105=0

We multiply all the terms by the denominator


-(1+105*2((+3x^2+6x+15x+30)))=0



We calculate terms in parentheses: -(1+105*2((+3x^2+6x+15x+30))), so:

1+105*2((+3x^2+6x+15x+30))

determiningTheFunctionDomain
105*2((+3x^2+6x+15x+30))+1

Wy multiply elements

210x((+1

Back to the equation:

-(210x((+1)



We add all the numbers together, and all the variables

-(210x(1=0

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