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(3x+15)(x+2)=0
We multiply parentheses ..
(+3x^2+6x+15x+30)=0
We get rid of parentheses
3x^2+6x+15x+30=0
We add all the numbers together, and all the variables
3x^2+21x+30=0
a = 3; b = 21; c = +30;
Δ = b2-4ac
Δ = 212-4·3·30
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81}=9$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-9}{2*3}=\frac{-30}{6} =-5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+9}{2*3}=\frac{-12}{6} =-2 $
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