6u-4+2(2u+3)=-2(u+2)

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Solution for 6u-4+2(2u+3)=-2(u+2) equation: 



6u-4+2(2u+3)=-2(u+2)

We move all terms to the left:

6u-4+2(2u+3)-(-2(u+2))=0

We multiply parentheses

6u+4u-(-2(u+2))+6-4=0



We calculate terms in parentheses: -(-2(u+2)), so:

-2(u+2)

We multiply parentheses

-2u-4

Back to the equation:

-(-2u-4)



We add all the numbers together, and all the variables

10u-(-2u-4)+2=0

We get rid of parentheses

10u+2u+4+2=0

We add all the numbers together, and all the variables

12u+6=0

We move all terms containing u to the left, all other terms to the right

12u=-6

u=-6/12

u=-1/2

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