5(y-5)-4=-4(-4y+8)-5y

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Solution for 5(y-5)-4=-4(-4y+8)-5y equation: 



5(y-5)-4=-4(-4y+8)-5y

We move all terms to the left:

5(y-5)-4-(-4(-4y+8)-5y)=0

We multiply parentheses

5y-(-4(-4y+8)-5y)-25-4=0



We calculate terms in parentheses: -(-4(-4y+8)-5y), so:

-4(-4y+8)-5y

We add all the numbers together, and all the variables

-5y-4(-4y+8)

We multiply parentheses

-5y+16y-32

We add all the numbers together, and all the variables

11y-32

Back to the equation:

-(11y-32)



We add all the numbers together, and all the variables

5y-(11y-32)-29=0

We get rid of parentheses

5y-11y+32-29=0

We add all the numbers together, and all the variables

-6y+3=0

We move all terms containing y to the left, all other terms to the right

-6y=-3

y=-3/-6

y=1/2

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