12(x-3)+18=(2x-3)

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Solution for 12(x-3)+18=(2x-3) equation: 



12(x-3)+18=(2x-3)

We move all terms to the left:

12(x-3)+18-((2x-3))=0

We multiply parentheses

12x-((2x-3))-36+18=0



We calculate terms in parentheses: -((2x-3)), so:

(2x-3)

We get rid of parentheses

2x-3

Back to the equation:

-(2x-3)



We add all the numbers together, and all the variables

12x-(2x-3)-18=0

We get rid of parentheses

12x-2x+3-18=0

We add all the numbers together, and all the variables

10x-15=0

We move all terms containing x to the left, all other terms to the right

10x=15

x=15/10

x=1+1/2

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