13=(5/2)(5x-4)

Solution for 13=(5/2)(5x-4) equation:

13=(5/2)(5x-4)

We move all terms to the left:

13-((5/2)(5x-4))=0


Domain of the equation: 2)(5x-4))!=0

x∈R


We add all the numbers together, and all the variables

-((+5/2)(5x-4))+13=0

We multiply parentheses ..

-((+25x^2+5/2*-4))+13=0

We multiply all the terms by the denominator


-((+25x^2+5+13*2*-4))=0


We calculate terms in parentheses: -((+25x^2+5+13*2*-4)), so:

(+25x^2+5+13*2*-4)

We get rid of parentheses

25x^2+5-4+13*2*

We add all the numbers together, and all the variables

25x^2

Back to the equation:

-(25x^2)


a = -25; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-25)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-50}=0$