-4x(3x-5)=-13(x-2)

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Solution for -4x(3x-5)=-13(x-2) equation: 



-4x(3x-5)=-13(x-2)

We move all terms to the left:

-4x(3x-5)-(-13(x-2))=0

We multiply parentheses

-12x^2+20x-(-13(x-2))=0



We calculate terms in parentheses: -(-13(x-2)), so:

-13(x-2)

We multiply parentheses

-13x+26

Back to the equation:

-(-13x+26)



We get rid of parentheses

-12x^2+20x+13x-26=0

We add all the numbers together, and all the variables

-12x^2+33x-26=0

a = -12; b = 33; c = -26;
Δ = b2-4ac
Δ = 332-4·(-12)·(-26)
Δ = -159
Delta is less than zero, so there is no solution for the equation

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