20-10+22=2c+10c-5c

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Solution for 20-10+22=2c+10c-5c equation: 



20-10+22=2c+10c-5c

We move all terms to the left:

20-10+22-(2c+10c-5c)=0

We add all the numbers together, and all the variables

-(+7c)+20-10+22=0

We add all the numbers together, and all the variables

-(+7c)+32=0

We get rid of parentheses

-7c+32=0

We move all terms containing c to the left, all other terms to the right

-7c=-32

c=-32/-7

c=4+4/7

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