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6t^2-25t-9=0
a = 6; b = -25; c = -9;
Δ = b2-4ac
Δ = -252-4·6·(-9)
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{841}=29$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-29}{2*6}=\frac{-4}{12} =-1/3 $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+29}{2*6}=\frac{54}{12} =4+1/2 $
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