6n2-7n-49=0

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Solution for 6n2-7n-49=0 equation:



6n^2-7n-49=0
a = 6; b = -7; c = -49;
Δ = b2-4ac
Δ = -72-4·6·(-49)
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1225}=35$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-35}{2*6}=\frac{-28}{12} =-2+1/3 $
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+35}{2*6}=\frac{42}{12} =3+1/2 $

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