(4x+8)=(7x+2/4)

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Solution for (4x+8)=(7x+2/4) equation:



(4x+8)=(7x+2/4)
We move all terms to the left:
(4x+8)-((7x+2/4))=0
We add all the numbers together, and all the variables
(4x+8)-((+7x+2/4))=0
We get rid of parentheses
4x-((+7x+2/4))+8=0
We multiply all the terms by the denominator
4x*4))-((+7x+2+8*4))=0
We add all the numbers together, and all the variables
4x*4))-((7x+34))=0
We add all the numbers together, and all the variables
4x*4))-((7x=0
Wy multiply elements
16x^2=0
a = 16; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·16·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{32}=0$

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