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4/5x+3=5/3x-6
We move all terms to the left:
4/5x+3-(5/3x-6)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 3x-6)!=0We get rid of parentheses
x∈R
4/5x-5/3x+6+3=0
We calculate fractions
12x/15x^2+(-25x)/15x^2+6+3=0
We add all the numbers together, and all the variables
12x/15x^2+(-25x)/15x^2+9=0
We multiply all the terms by the denominator
12x+(-25x)+9*15x^2=0
Wy multiply elements
135x^2+12x+(-25x)=0
We get rid of parentheses
135x^2+12x-25x=0
We add all the numbers together, and all the variables
135x^2-13x=0
a = 135; b = -13; c = 0;
Δ = b2-4ac
Δ = -132-4·135·0
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{169}=13$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-13}{2*135}=\frac{0}{270} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+13}{2*135}=\frac{26}{270} =13/135 $
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