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2n^2-5n-88=0
a = 2; b = -5; c = -88;
Δ = b2-4ac
Δ = -52-4·2·(-88)
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{729}=27$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-27}{2*2}=\frac{-22}{4} =-5+1/2 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+27}{2*2}=\frac{32}{4} =8 $
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