6=2(3+4)(n-7)

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Solution for 6=2(3+4)(n-7) equation: 



6=2(3+4)(n-7)

We move all terms to the left:

6-(2(3+4)(n-7))=0

We add all the numbers together, and all the variables

-(27(n-7))+6=0



We calculate terms in parentheses: -(27(n-7)), so:

27(n-7)

We multiply parentheses

27n-189

Back to the equation:

-(27n-189)



We get rid of parentheses

-27n+189+6=0

We add all the numbers together, and all the variables

-27n+195=0

We move all terms containing n to the left, all other terms to the right

-27n=-195

n=-195/-27

n=7+2/9

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