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2x(x+35)=360
We move all terms to the left:
2x(x+35)-(360)=0
We multiply parentheses
2x^2+70x-360=0
a = 2; b = 70; c = -360;
Δ = b2-4ac
Δ = 702-4·2·(-360)
Δ = 7780
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{7780}=\sqrt{4*1945}=\sqrt{4}*\sqrt{1945}=2\sqrt{1945}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(70)-2\sqrt{1945}}{2*2}=\frac{-70-2\sqrt{1945}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(70)+2\sqrt{1945}}{2*2}=\frac{-70+2\sqrt{1945}}{4} $
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