-2(-8y+7)-6y=6(y-3)-2

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Solution for -2(-8y+7)-6y=6(y-3)-2 equation: 



-2(-8y+7)-6y=6(y-3)-2

We move all terms to the left:

-2(-8y+7)-6y-(6(y-3)-2)=0

We add all the numbers together, and all the variables

-6y-2(-8y+7)-(6(y-3)-2)=0

We multiply parentheses

-6y+16y-(6(y-3)-2)-14=0



We calculate terms in parentheses: -(6(y-3)-2), so:

6(y-3)-2

We multiply parentheses

6y-18-2

We add all the numbers together, and all the variables

6y-20

Back to the equation:

-(6y-20)



We add all the numbers together, and all the variables

10y-(6y-20)-14=0

We get rid of parentheses

10y-6y+20-14=0

We add all the numbers together, and all the variables

4y+6=0

We move all terms containing y to the left, all other terms to the right

4y=-6

y=-6/4

y=-1+1/2

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