6=1.2d(3d-5)

Solution for 6=1.2d(3d-5) equation:

6=1.2d(3d-5)

We move all terms to the left:

6-(1.2d(3d-5))=0


We calculate terms in parentheses: -(1.2d(3d-5)), so:

1.2d(3d-5)

We multiply parentheses

3d^2-5d

Back to the equation:

-(3d^2-5d)


We get rid of parentheses

-3d^2+5d+6=0

a = -3; b = 5; c = +6;
Δ = b2-4ac
Δ = 52-4·(-3)·6
Δ = 97
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{97}}{2*-3}=\frac{-5-\sqrt{97}}{-6}
$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{97}}{2*-3}=\frac{-5+\sqrt{97}}{-6}
$