-5(3x-3)=2(x-45)-65

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Solution for -5(3x-3)=2(x-45)-65 equation: 



-5(3x-3)=2(x-45)-65

We move all terms to the left:

-5(3x-3)-(2(x-45)-65)=0

We multiply parentheses

-15x-(2(x-45)-65)+15=0



We calculate terms in parentheses: -(2(x-45)-65), so:

2(x-45)-65

We multiply parentheses

2x-90-65

We add all the numbers together, and all the variables

2x-155

Back to the equation:

-(2x-155)



We get rid of parentheses

-15x-2x+155+15=0

We add all the numbers together, and all the variables

-17x+170=0

We move all terms containing x to the left, all other terms to the right

-17x=-170

x=-170/-17

x=+10

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