68+(2x-20)=3x

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Solution for 68+(2x-20)=3x equation: 



68+(2x-20)=3x

We move all terms to the left:

68+(2x-20)-(3x)=0

We add all the numbers together, and all the variables

-3x+(2x-20)+68=0

We get rid of parentheses

-3x+2x-20+68=0

We add all the numbers together, and all the variables

-1x+48=0

We move all terms containing x to the left, all other terms to the right

-x=-48

x=-48/-1

x=+48

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