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2(3x-1)+5=(x+6)-2
We move all terms to the left:
2(3x-1)+5-((x+6)-2)=0
We multiply parentheses
6x-((x+6)-2)-2+5=0
We calculate terms in parentheses: -((x+6)-2), so:We add all the numbers together, and all the variables
(x+6)-2
We get rid of parentheses
x+6-2
We add all the numbers together, and all the variables
x+4
Back to the equation:
-(x+4)
6x-(x+4)+3=0
We get rid of parentheses
6x-x-4+3=0
We add all the numbers together, and all the variables
5x-1=0
We move all terms containing x to the left, all other terms to the right
5x=1
x=1/5
x=1/5
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