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3(5x+2)=4(x-11)
We move all terms to the left:
3(5x+2)-(4(x-11))=0
We multiply parentheses
15x-(4(x-11))+6=0
We calculate terms in parentheses: -(4(x-11)), so:We get rid of parentheses
4(x-11)
We multiply parentheses
4x-44
Back to the equation:
-(4x-44)
15x-4x+44+6=0
We add all the numbers together, and all the variables
11x+50=0
We move all terms containing x to the left, all other terms to the right
11x=-50
x=-50/11
x=-4+6/11
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