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65=2x+(2x-5)+x
We move all terms to the left:
65-(2x+(2x-5)+x)=0
We calculate terms in parentheses: -(2x+(2x-5)+x), so:We get rid of parentheses
2x+(2x-5)+x
We add all the numbers together, and all the variables
3x+(2x-5)
We get rid of parentheses
3x+2x-5
We add all the numbers together, and all the variables
5x-5
Back to the equation:
-(5x-5)
-5x+5+65=0
We add all the numbers together, and all the variables
-5x+70=0
We move all terms containing x to the left, all other terms to the right
-5x=-70
x=-70/-5
x=+14
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