2/3x+10=5/2(-x+3)

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Solution for 2/3x+10=5/2(-x+3) equation: 



2/3x+10=5/2(-x+3)

We move all terms to the left:

2/3x+10-(5/2(-x+3))=0



Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R





Domain of the equation: 2(-x+3))!=0

x∈R



We add all the numbers together, and all the variables

2/3x-(5/2(-1x+3))+10=0

We calculate fractions


(4x(-)/(6x^2(-)+(-(5*3x)/(6x^2(-)+10=0

We can not solve this equation

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