1/2(x+2)=1/3(x+6)

Solution for 1/2(x+2)=1/3(x+6) equation:

1/2(x+2)=1/3(x+6)

We move all terms to the left:

1/2(x+2)-(1/3(x+6))=0


Domain of the equation: 2(x+2)!=0

x∈R



Domain of the equation: 3(x+6))!=0

x∈R


We calculate fractions


(3xx/(2(x+2)*3(x+6)))+(-2xx/(2(x+2)*3(x+6)))=0


We calculate terms in parentheses: +(3xx/(2(x+2)*3(x+6))), so:

3xx/(2(x+2)*3(x+6))

We multiply all the terms by the denominator


3xx

Back to the equation:

+(3xx)



We calculate terms in parentheses: +(-2xx/(2(x+2)*3(x+6))), so:

-2xx/(2(x+2)*3(x+6))

We multiply all the terms by the denominator


-2xx

Back to the equation:

+(-2xx)


We get rid of parentheses

3xx-2xx=0