65=((x-3)x)/2

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Solution for 65=((x-3)x)/2 equation:



65=((x-3)x)/2
We move all terms to the left:
65-(((x-3)x)/2)=0
We multiply all the terms by the denominator
-(((x-3)x)+65*2)=0
We calculate terms in parentheses: -(((x-3)x)+65*2), so:
((x-3)x)+65*2
We add all the numbers together, and all the variables
((x-3)x)+130
We calculate terms in parentheses: +((x-3)x), so:
(x-3)x
We multiply parentheses
x^2-3x
Back to the equation:
+(x^2-3x)
We get rid of parentheses
x^2-3x+130
Back to the equation:
-(x^2-3x+130)
We get rid of parentheses
-x^2+3x-130=0
We add all the numbers together, and all the variables
-1x^2+3x-130=0
a = -1; b = 3; c = -130;
Δ = b2-4ac
Δ = 32-4·(-1)·(-130)
Δ = -511
Delta is less than zero, so there is no solution for the equation

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