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49r^2=100
We move all terms to the left:
49r^2-(100)=0
a = 49; b = 0; c = -100;
Δ = b2-4ac
Δ = 02-4·49·(-100)
Δ = 19600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{19600}=140$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-140}{2*49}=\frac{-140}{98} =-1+3/7 $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+140}{2*49}=\frac{140}{98} =1+3/7 $
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