64=v2/5+19

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Solution for 64=v2/5+19 equation:



64=v2/5+19
We move all terms to the left:
64-(v2/5+19)=0
We get rid of parentheses
-v2/5-19+64=0
We multiply all the terms by the denominator
-v2-19*5+64*5=0
We add all the numbers together, and all the variables
-1v^2+225=0
a = -1; b = 0; c = +225;
Δ = b2-4ac
Δ = 02-4·(-1)·225
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{900}=30$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-30}{2*-1}=\frac{-30}{-2} =+15 $
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+30}{2*-1}=\frac{30}{-2} =-15 $

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