4c-2(c+2)=11-(2c-5)

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Solution for 4c-2(c+2)=11-(2c-5) equation: 



4c-2(c+2)=11-(2c-5)

We move all terms to the left:

4c-2(c+2)-(11-(2c-5))=0

We multiply parentheses

4c-2c-(11-(2c-5))-4=0



We calculate terms in parentheses: -(11-(2c-5)), so:

11-(2c-5)

determiningTheFunctionDomain
-(2c-5)+11

We get rid of parentheses

-2c+5+11

We add all the numbers together, and all the variables

-2c+16

Back to the equation:

-(-2c+16)



We add all the numbers together, and all the variables

2c-(-2c+16)-4=0

We get rid of parentheses

2c+2c-16-4=0

We add all the numbers together, and all the variables

4c-20=0

We move all terms containing c to the left, all other terms to the right

4c=20

c=20/4

c=5

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