63x=+27x2

Solution for 63x=+27x2 equation:

63x=+27x^2

We move all terms to the left:

63x-(+27x^2)=0

We get rid of parentheses

-27x^2+63x=0

a = -27; b = 63; c = 0;
Δ = b2-4ac
Δ = 632-4·(-27)·0
Δ = 3969
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3969}=63$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(63)-63}{2*-27}=\frac{-126}{-54}
=2+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(63)+63}{2*-27}=\frac{0}{-54}
=0
$