(2b-7)/5=(b-2)4

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Solution for (2b-7)/5=(b-2)4 equation: 



(2b-7)/5=(b-2)4

We move all terms to the left:

(2b-7)/5-((b-2)4)=0

We multiply all the terms by the denominator


(2b-7)-(((b-2)4))*5=0

We get rid of parentheses

2b-(((b-2)4))*5-7=0

We move all terms containing b to the left, all other terms to the right

2b-(((b-2)4))*5=7

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