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3x(5x+20x)=56
We move all terms to the left:
3x(5x+20x)-(56)=0
We add all the numbers together, and all the variables
3x(+25x)-56=0
We multiply parentheses
75x^2-56=0
a = 75; b = 0; c = -56;
Δ = b2-4ac
Δ = 02-4·75·(-56)
Δ = 16800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{16800}=\sqrt{400*42}=\sqrt{400}*\sqrt{42}=20\sqrt{42}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20\sqrt{42}}{2*75}=\frac{0-20\sqrt{42}}{150} =-\frac{20\sqrt{42}}{150} =-\frac{2\sqrt{42}}{15} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20\sqrt{42}}{2*75}=\frac{0+20\sqrt{42}}{150} =\frac{20\sqrt{42}}{150} =\frac{2\sqrt{42}}{15} $
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