627=x(5x+2)

Solution for 627=x(5x+2) equation:

627=x(5x+2)

We move all terms to the left:

627-(x(5x+2))=0


We calculate terms in parentheses: -(x(5x+2)), so:

x(5x+2)

We multiply parentheses

5x^2+2x

Back to the equation:

-(5x^2+2x)


We get rid of parentheses

-5x^2-2x+627=0

a = -5; b = -2; c = +627;
Δ = b2-4ac
Δ = -22-4·(-5)·627
Δ = 12544
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{12544}=112$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-112}{2*-5}=\frac{-110}{-10}
=+11
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+112}{2*-5}=\frac{114}{-10}
=-11+2/5
$