9x-(2x+1)=8-2(-3x+3)

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Solution for 9x-(2x+1)=8-2(-3x+3) equation: 



9x-(2x+1)=8-2(-3x+3)

We move all terms to the left:

9x-(2x+1)-(8-2(-3x+3))=0

We get rid of parentheses

9x-2x-(8-2(-3x+3))-1=0



We calculate terms in parentheses: -(8-2(-3x+3)), so:

8-2(-3x+3)

determiningTheFunctionDomain
-2(-3x+3)+8

We multiply parentheses

6x-6+8

We add all the numbers together, and all the variables

6x+2

Back to the equation:

-(6x+2)



We add all the numbers together, and all the variables

7x-(6x+2)-1=0

We get rid of parentheses

7x-6x-2-1=0

We add all the numbers together, and all the variables

x-3=0

We move all terms containing x to the left, all other terms to the right

x=3

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