Y=10x2-7x-12x=3

Solution for Y=10x2-7x-12x=3 equation:

=10Y^2-7Y-12Y=3

We move all terms to the left:

-(10Y^2-7Y-12Y)=0

We get rid of parentheses

-10Y^2+7Y+12Y=0

We add all the numbers together, and all the variables

-10Y^2+19Y=0

a = -10; b = 19; c = 0;
Δ = b2-4ac
Δ = 192-4·(-10)·0
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{361}=19$
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19)-19}{2*-10}=\frac{-38}{-20}
=1+9/10
$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19)+19}{2*-10}=\frac{0}{-20}
=0
$