625+2500=c2

Solution for 625+2500=c2 equation:

625+2500=c2

We move all terms to the left:

625+2500-(c2)=0

We add all the numbers together, and all the variables

-1c^2+3125=0

a = -1; b = 0; c = +3125;
Δ = b2-4ac
Δ = 02-4·(-1)·3125
Δ = 12500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{12500}=\sqrt{2500*5}=\sqrt{2500}*\sqrt{5}=50\sqrt{5}$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-50\sqrt{5}}{2*-1}=\frac{0-50\sqrt{5}}{-2}
=-\frac{50\sqrt{5}}{-2}
=-\frac{25\sqrt{5}}{-1}
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+50\sqrt{5}}{2*-1}=\frac{0+50\sqrt{5}}{-2}
=\frac{50\sqrt{5}}{-2}
=\frac{25\sqrt{5}}{-1}
$