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f(2)=-4(f+3)
We move all terms to the left:
f(2)-(-4(f+3))=0
We add all the numbers together, and all the variables
f^2-(-4(f+3))=0
We calculate terms in parentheses: -(-4(f+3)), so:We get rid of parentheses
-4(f+3)
We multiply parentheses
-4f-12
Back to the equation:
-(-4f-12)
f^2+4f+12=0
a = 1; b = 4; c = +12;
Δ = b2-4ac
Δ = 42-4·1·12
Δ = -32
Delta is less than zero, so there is no solution for the equation
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