8(y-4)=7y-38

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Solution for 8(y-4)=7y-38 equation: 



8(y-4)=7y-38

We move all terms to the left:

8(y-4)-(7y-38)=0

We multiply parentheses

8y-(7y-38)-32=0

We get rid of parentheses

8y-7y+38-32=0

We add all the numbers together, and all the variables

y+6=0

We move all terms containing y to the left, all other terms to the right

y=-6

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