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2/6x=4/9x-1
We move all terms to the left:
2/6x-(4/9x-1)=0
Domain of the equation: 6x!=0
x!=0/6
x!=0
x∈R
Domain of the equation: 9x-1)!=0We get rid of parentheses
x∈R
2/6x-4/9x+1=0
We calculate fractions
18x/54x^2+(-24x)/54x^2+1=0
We multiply all the terms by the denominator
18x+(-24x)+1*54x^2=0
Wy multiply elements
54x^2+18x+(-24x)=0
We get rid of parentheses
54x^2+18x-24x=0
We add all the numbers together, and all the variables
54x^2-6x=0
a = 54; b = -6; c = 0;
Δ = b2-4ac
Δ = -62-4·54·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-6}{2*54}=\frac{0}{108} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+6}{2*54}=\frac{12}{108} =1/9 $
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